![Calculus] Can anyone explain in layman's terms why the limit of sin(pi/x) as x --> 0 is null? : r/learnmath Calculus] Can anyone explain in layman's terms why the limit of sin(pi/x) as x --> 0 is null? : r/learnmath](https://external-preview.redd.it/qbxOoh3XQjKwU39BU5kpfv0ug4Z0NVdfURsusIjhzms.jpg?auto=webp&s=af6c0c060d09dc25f75cecdd097001cba2e7d6cd)
Calculus] Can anyone explain in layman's terms why the limit of sin(pi/x) as x --> 0 is null? : r/learnmath
![limits - The behavior of the graph of $f(x) = \sin (\pi/x)$ as x approaches 0, Why? - Mathematics Stack Exchange limits - The behavior of the graph of $f(x) = \sin (\pi/x)$ as x approaches 0, Why? - Mathematics Stack Exchange](https://i.stack.imgur.com/bEaQ5.gif)
limits - The behavior of the graph of $f(x) = \sin (\pi/x)$ as x approaches 0, Why? - Mathematics Stack Exchange
![Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is](https://haygot.s3.amazonaws.com/questions/1553048_121246_ans_1a21ea3929b041efa356547e6dbebd40.jpg)
Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is
![Find the area under y = sin(pi*x) for 1 less than or equal to x less than or equal to 5. | Homework.Study.com Find the area under y = sin(pi*x) for 1 less than or equal to x less than or equal to 5. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/sinpix6037145647900625173.jpg)
Find the area under y = sin(pi*x) for 1 less than or equal to x less than or equal to 5. | Homework.Study.com
![Prove that: sin(pi+x)cos (pi2+x)tan (3pi2-x)cot(2pi-x)sin(2pi-x)cos(2pi-x) ( - x)sin (3pi2-x) = n pi + pi 4 where n∈ N Prove that: sin(pi+x)cos (pi2+x)tan (3pi2-x)cot(2pi-x)sin(2pi-x)cos(2pi-x) ( - x)sin (3pi2-x) = n pi + pi 4 where n∈ N](https://haygot.s3.amazonaws.com/questions/1609504_1665201_ans_13d0466d15454f85a744e48b20c675b6.jpeg)
Prove that: sin(pi+x)cos (pi2+x)tan (3pi2-x)cot(2pi-x)sin(2pi-x)cos(2pi-x) ( - x)sin (3pi2-x) = n pi + pi 4 where n∈ N
![trigonometric polynomials - Solutions of equation $\sin \pi x_1\sin \pi x_2=\sin \pi x_3\sin \pi x_4$ - MathOverflow trigonometric polynomials - Solutions of equation $\sin \pi x_1\sin \pi x_2=\sin \pi x_3\sin \pi x_4$ - MathOverflow](https://i.stack.imgur.com/eBuTx.jpg)