![IB Stats] Question 7b: Why is the maximum of P(AnB) equal to P(A) and not equal to P(B), which gives a max. value of 1? : r/HomeworkHelp IB Stats] Question 7b: Why is the maximum of P(AnB) equal to P(A) and not equal to P(B), which gives a max. value of 1? : r/HomeworkHelp](https://preview.redd.it/xk3z57t6v3n71.png?auto=webp&s=ae81a6e376f4c8b748a21b33e6d2e63423c53fa4)
IB Stats] Question 7b: Why is the maximum of P(AnB) equal to P(A) and not equal to P(B), which gives a max. value of 1? : r/HomeworkHelp
![SOLVED: Let A and B be events in a sample space such that a) P(A)=0.2 P(AnB) =0.15 and P((AUB) ) = 0.3 Calculate: P(AT ) ; P(AIB); P(B); P(B"IAc nB) ; vi) SOLVED: Let A and B be events in a sample space such that a) P(A)=0.2 P(AnB) =0.15 and P((AUB) ) = 0.3 Calculate: P(AT ) ; P(AIB); P(B); P(B"IAc nB) ; vi)](https://cdn.numerade.com/ask_images/c91a1fece2ad48b2b6834671e156a5ae.jpg)
SOLVED: Let A and B be events in a sample space such that a) P(A)=0.2 P(AnB) =0.15 and P((AUB) ) = 0.3 Calculate: P(AT ) ; P(AIB); P(B); P(B"IAc nB) ; vi)
![SOLVED: The Additive Law of Probability states that P(A U B) = P(A) + P(B) - P(A n B). Since P(A U B) < 1, we get P(A) + P(B) - P(An SOLVED: The Additive Law of Probability states that P(A U B) = P(A) + P(B) - P(A n B). Since P(A U B) < 1, we get P(A) + P(B) - P(An](https://cdn.numerade.com/ask_images/791cd00344404c2dac125440af1213d1.jpg)
SOLVED: The Additive Law of Probability states that P(A U B) = P(A) + P(B) - P(A n B). Since P(A U B) < 1, we get P(A) + P(B) - P(An
![Probability Rules Cheat Sheet. Basic probability rules with examples… | by rita | Data Comet | Medium Probability Rules Cheat Sheet. Basic probability rules with examples… | by rita | Data Comet | Medium](https://miro.medium.com/v2/resize:fit:1200/1*nPxOKWpyD80uqqDMluoYgA.png)
Probability Rules Cheat Sheet. Basic probability rules with examples… | by rita | Data Comet | Medium
![If P(AnB) / P(B) = P(A|B) [given]then P(AuB) / P(A) OR P(AuB) / P(B) = I wanted the - Maths - Probability - 3773778 | Meritnation.com If P(AnB) / P(B) = P(A|B) [given]then P(AuB) / P(A) OR P(AuB) / P(B) = I wanted the - Maths - Probability - 3773778 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/4135575/2013_02_14_17_32_39/mathmlequation6375385430541647236.png)